5v^2+3v-14=0

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Solution for 5v^2+3v-14=0 equation: 



5v^2+3v-14=0

a = 5; b = 3; c = -14;
Δ = b2-4ac
Δ = 32-4·5·(-14)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$


$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-17}{2*5}=\frac{-20}{10}
=-2
$


$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+17}{2*5}=\frac{14}{10}
=1+2/5
$

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